document.write( "Question 173693This question is from textbook Algebra Structure and Method Book 1
\n" ); document.write( ": I would appreciate your help on the following problem: The two digits in the numerator of a fraction whose value is 4/7 are reversed in its demoninator. The reciprocal of the fraction is the value obtained when 16 is added to the original numerator and 5 is subtracted from the original demonimator. Find the original fraction. I have 10t+u/10u+t=4/7; 10u+t/10t+u=10t+u+16/10u+t-5.
\n" ); document.write( "7(10t+u)=4(10u+t), 70t+7u=40u+4t, 66t=33u, t=3/6u. I'm not sure where to go from there. Thank you so much for any help you can give me. I appreciate it so much!
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Algebra.Com's Answer #128574 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I would appreciate your help on the following problem:
\n" ); document.write( "The two digits in the numerator of a fraction whose value is 4/7 are reversed in its denominator.
\n" ); document.write( "I have 10t+u/10u+t=4/7
\n" ); document.write( "Rearrange:
\n" ); document.write( "7(10t+u) = 4(10u+t)
\n" ); document.write( "70t + 7u = 40u+4t
\n" ); document.write( "66t - 33u = 0
\n" ); document.write( "t = (1/2)u
\n" ); document.write( "-----------------------------\r
\n" ); document.write( "\n" ); document.write( "The reciprocal of the fraction is the value obtained when 16 is added to the original numerator and 5 is subtracted from the original denominator.
\n" ); document.write( "(10u+t)/(10t+u) = [10t+u+16]/[10u+t-5]
\n" ); document.write( "Rearrange:
\n" ); document.write( "(10u+t)(10u+t-5) = (10t+u)(10t+u+16)
\n" ); document.write( "[(10u+t)^2 - 5(10u+t)] = [(10t+u)^2 + 16(10t+u)]\r
\n" ); document.write( "\n" ); document.write( "[100u^2 + 20tu + t^2 -50u - 5t] = [100t^2 + 20tu + u^2 + 160t + 16u]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "[99u^2 - 99t^2 -66u - 165t] = 0\r
\n" ); document.write( "\n" ); document.write( "----------------------------------------------
\n" ); document.write( "Substitute t = (1/2)u into the last equation to solve for \"u\":\r
\n" ); document.write( "\n" ); document.write( "Comment: This is a messy problem. I'll leave the substitution to you.
\n" ); document.write( "I get u = 2 so t = 1
\n" ); document.write( "Number: 12\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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