document.write( "Question 173699This question is from textbook Algebra 1: A Teaching Textbook
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document.write( ": Harold invested $30,000 in various stocks and bonds. He earned 6% on his bonds and 12% on his stocks. If Harold's total profit on both types of investments was $2,460, how much of the $30,000 did he invest in bonds?\r
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document.write( "At first I thought this had to have two variables, but I couldn't work it out. I tried adding .06(30,000)x + .12(30,000)2x(because .12 is twice .06) =2460 But the interest rate and the amount invested don't seem related! Please help!
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Algebra.Com's Answer #128563 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! Very good you were very close \n" ); document.write( ": \n" ); document.write( "let the amounts invested in 6% and 12% be x and y respectively \n" ); document.write( ": \n" ); document.write( "this is where you had trouble. We know that x+y=30000...so x=30000-y...lets call that eq 1 \n" ); document.write( ": \n" ); document.write( ".06x+.12y=2460.....eq 2 \n" ); document.write( ": \n" ); document.write( "now plug in x's value of 30000-y into eq 2 \n" ); document.write( ": \n" ); document.write( ".06(30000-y)+.12y=2460 \n" ); document.write( ": \n" ); document.write( "1800-.06y+.12y=2460 \n" ); document.write( ": \n" ); document.write( ".06y=660 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " |