document.write( "Question 173699This question is from textbook Algebra 1: A Teaching Textbook
\n" ); document.write( ": Harold invested $30,000 in various stocks and bonds. He earned 6% on his bonds and 12% on his stocks. If Harold's total profit on both types of investments was $2,460, how much of the $30,000 did he invest in bonds?\r
\n" ); document.write( "\n" ); document.write( "At first I thought this had to have two variables, but I couldn't work it out. I tried adding .06(30,000)x + .12(30,000)2x(because .12 is twice .06) =2460 But the interest rate and the amount invested don't seem related! Please help!
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Algebra.Com's Answer #128563 by Mathtut(3670)\"\" \"About 
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Very good you were very close
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\n" ); document.write( "let the amounts invested in 6% and 12% be x and y respectively
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\n" ); document.write( "this is where you had trouble. We know that x+y=30000...so x=30000-y...lets call that eq 1
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\n" ); document.write( ".06x+.12y=2460.....eq 2
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\n" ); document.write( "now plug in x's value of 30000-y into eq 2
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\n" ); document.write( ".06(30000-y)+.12y=2460
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\n" ); document.write( "1800-.06y+.12y=2460
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\n" ); document.write( ".06y=660
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\n" ); document.write( "\"highlight%28y=11000%29\"invested at 12 %
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\n" ); document.write( "\"highlight%28x=30000-11000=19000%29\"invested at 6%
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