document.write( "Question 173690: On a 135-mile bycycle excursion, Maria averaged 5 mph faster for the first 60 miles than she did for the last 75 miles. The entire trip took 8 hours. Find the rate for the first 60 miles. \n" ); document.write( "
Algebra.Com's Answer #128557 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
you have to set this up as 2 different parts of a lonnnnnnnnnggggggg trip.
\n" ); document.write( ":
\n" ); document.write( "lets call the 2nd part of the trips rate r and time t and
\n" ); document.write( ":
\n" ); document.write( "so then we will call the first part of the trips rate r+5 and the time 8-t(total time minus 2nd part of the trips time(t))
\n" ); document.write( ":
\n" ); document.write( "so
\n" ); document.write( "75=rt......................eq 1
\n" ); document.write( "60=(r+5)(8-t)..........eq 2
\n" ); document.write( ":
\n" ); document.write( "lets rewrite eq 1 to t=75/r and plug t's value into eq 2
\n" ); document.write( ":
\n" ); document.write( "60=(r+5)(8-(75/r))
\n" ); document.write( ":
\n" ); document.write( "60=(r+5)((8r-75)/r).........now multiply both sides by r
\n" ); document.write( ":
\n" ); document.write( "60r=(r+5)(8r-75)
\n" ); document.write( ":
\n" ); document.write( "\"60r=8r%5E2-75r%2B40r-375\"
\n" ); document.write( "\"8r%5E2-95r-375%2B0\"
\n" ); document.write( ":
\n" ); document.write( "throw out negative answer\"system%28r=15%2Cr=-3.125%29\"
\n" ); document.write( ":
\n" ); document.write( "therefore rate on 75 mile part of trip is 15mph
\n" ); document.write( ":
\n" ); document.write( "rate on 60 mile part of trip is \"highlight%28r%2B5=15%2B5-20%29\"mph
\n" ); document.write( ":
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"8x%5E2%2B-95x%2B-375+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-95%29%5E2-4%2A8%2A-375=21025\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=21025 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--95%2B-sqrt%28+21025+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%28-95%29%2Bsqrt%28+21025+%29%29%2F2%5C8+=+15\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-95%29-sqrt%28+21025+%29%29%2F2%5C8+=+-3.125\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"8x%5E2%2B-95x%2B-375\" can be factored:
\n" ); document.write( " \"8x%5E2%2B-95x%2B-375+=+%28x-15%29%2A%28x--3.125%29\"
\n" ); document.write( " Again, the answer is: 15, -3.125.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+8%2Ax%5E2%2B-95%2Ax%2B-375+%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );