document.write( "Question 173690: On a 135-mile bycycle excursion, Maria averaged 5 mph faster for the first 60 miles than she did for the last 75 miles. The entire trip took 8 hours. Find the rate for the first 60 miles. \n" ); document.write( "
Algebra.Com's Answer #128557 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! you have to set this up as 2 different parts of a lonnnnnnnnnggggggg trip. \n" ); document.write( ": \n" ); document.write( "lets call the 2nd part of the trips rate r and time t and \n" ); document.write( ": \n" ); document.write( "so then we will call the first part of the trips rate r+5 and the time 8-t(total time minus 2nd part of the trips time(t)) \n" ); document.write( ": \n" ); document.write( "so \n" ); document.write( "75=rt......................eq 1 \n" ); document.write( "60=(r+5)(8-t)..........eq 2 \n" ); document.write( ": \n" ); document.write( "lets rewrite eq 1 to t=75/r and plug t's value into eq 2 \n" ); document.write( ": \n" ); document.write( "60=(r+5)(8-(75/r)) \n" ); document.write( ": \n" ); document.write( "60=(r+5)((8r-75)/r).........now multiply both sides by r \n" ); document.write( ": \n" ); document.write( "60r=(r+5)(8r-75) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "throw out negative answer \n" ); document.write( ": \n" ); document.write( "therefore rate on 75 mile part of trip is 15mph \n" ); document.write( ": \n" ); document.write( "rate on 60 mile part of trip is \n" ); document.write( ": \n" ); document.write( "
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