document.write( "Question 173669: Log(x+99)-Logx=2 \n" ); document.write( "

Algebra.Com's Answer #128550 by Alan3354(69443) $\"\"$ $\"About$

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Log(x+99)-Logx=2
\n" ); document.write( "log((x+99)/x) = 2 Subtraction of logs --> division
\n" ); document.write( "raise 10 to the power of both sides
\n" ); document.write( "(x+99)/x = 100
\n" ); document.write( "x+99 = 100x
\n" ); document.write( "99 = 99x
\n" ); document.write( "x = 1\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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