document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173670>Question 173670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Asailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current. Plus how would you check your answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128546 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "R=D/T<BR>\n" );
document.write( "R=20/3=6.667 MPH. DOWN STREAM<BR>\n" );
document.write( "R=20/4=5 MPH. UP STREAM <BR>\n" );
document.write( "(6.667-5)/2=1.667/2=.833 MPH. FOR THE CURRENT.<BR>\n" );
document.write( "6.667-.833=5.833 SPEED OF THE BOAT.<BR>\n" );
document.write( "5+.833=5.833 DITTO. </SPAN>\n" );
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