document.write( "Question 173671: Jim has a total of 50 coins. Some are nickels and some are dimes. Altogether he has $4.15. How many dimes does he have? How many Nickels? show your work using algebra and the fiv step method. \n" ); document.write( "
Algebra.Com's Answer #128545 by checkley77(12844)\"\" \"About 
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D+N=50 OR D=50-N
\n" ); document.write( ".10D+.05N=4.15
\n" ); document.write( ".10(50-N)+.05N=4.15
\n" ); document.write( "5-.10N+.05N=4.15
\n" ); document.write( "-.05N=4.15-5
\n" ); document.write( ".05N=.85
\n" ); document.write( "N=.8/.05
\n" ); document.write( "N=17 IS THE NUMBER OF NICKLES.
\n" ); document.write( "50-17=33 NUMBER OF DIMES.
\n" ); document.write( "PROOF:
\n" ); document.write( ".10*33+.05*17=4.15
\n" ); document.write( "3.30+.85=4.15
\n" ); document.write( "4.15=4.15
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