document.write( "Question 173671: Jim has a total of 50 coins. Some are nickels and some are dimes. Altogether he has $4.15. How many dimes does he have? How many Nickels? show your work using algebra and the fiv step method. \n" ); document.write( "
Algebra.Com's Answer #128545 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D+N=50 OR D=50-N \n" ); document.write( ".10D+.05N=4.15 \n" ); document.write( ".10(50-N)+.05N=4.15 \n" ); document.write( "5-.10N+.05N=4.15 \n" ); document.write( "-.05N=4.15-5 \n" ); document.write( ".05N=.85 \n" ); document.write( "N=.8/.05 \n" ); document.write( "N=17 IS THE NUMBER OF NICKLES. \n" ); document.write( "50-17=33 NUMBER OF DIMES. \n" ); document.write( "PROOF: \n" ); document.write( ".10*33+.05*17=4.15 \n" ); document.write( "3.30+.85=4.15 \n" ); document.write( "4.15=4.15 \n" ); document.write( " \n" ); document.write( " |