document.write( "Question 173614This question is from textbook Introductory Algebra
\n" ); document.write( ": Solve the equation\r
\n" ); document.write( "\n" ); document.write( "sqrt (2x + 3) - sqrt (x + 1) = 1
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Algebra.Com's Answer #128483 by 303795(602)\"\" \"About 
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Add \"sqrt+%28x+%2B+1%29\" to each side of the equation
\n" ); document.write( "\"sqrt+%282x+%2B+3%29+-+sqrt+%28x+%2B+1%29%2B+sqrt+%28x+%2B+1%29+=+1+%2B+sqrt+%28x+%2B+1%29\"
\n" ); document.write( "\"sqrt+%282x+%2B+3%29+=+1+%2B+sqrt+%28x+%2B+1%29\"
\n" ); document.write( "Square each side of the equation
\n" ); document.write( "\"%282x+%2B+3%29+=+1+%2B+2%2Asqrt+%28x+%2B+1%29+%2B+%28x%2B1%29\"
\n" ); document.write( "\"2x+%2B+3+-+1+-+%28x+%2B+1%29+=+1+%2B+2%2Asqrt+%28x+%2B+1%29+%2B+%28x%2B1%29+-+1+-%28x%2B1%29\"
\n" ); document.write( "\"x+%2B+1++=+2%2Asqrt+%28x+%2B+1%29\"
\n" ); document.write( "Square each side of the equation again
\n" ); document.write( "\"x%5E2+%2B+2x+%2B+1+=+4%2A%28x+%2B+1%29\"
\n" ); document.write( "\"x%5E2+%2B+2x+%2B+1+=+4x+%2B+4\"
\n" ); document.write( "\"x%5E2+-+2x+-+3+=+0\"
\n" ); document.write( "\"%28x+%2B+1%29+%28x+-+3%29+=+0\"
\n" ); document.write( "ie x = -1 or x = 3
\n" ); document.write( "Substitute back into the original equation and test if they both work.
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