document.write( "Question 173626This question is from textbook Introductory Algebra
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document.write( ": Tom Quig traveled 280 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major accident. If the total time of travel was 8 hours, how many miles did he drive at the reduced speed? \n" );
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Algebra.Com's Answer #128477 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Tom Quig traveled 280 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major accident. If the total time of travel was 8 hours, how many miles did he drive at the reduced speed? \n" ); document.write( "------------------------------ \n" ); document.write( "Most-trip DATA: \n" ); document.write( "distance = x miles ; rate = 60 mph ; time = d/r = x/60 hrs. \n" ); document.write( "---------------------- \n" ); document.write( "Slow part DATA: \n" ); document.write( "distance = 280-x miles ; rate = 10 mph ; time = d/r = (280-x)/10 hrs \n" ); document.write( "------------------------ \n" ); document.write( "EQUATION: \n" ); document.write( "time + time = 8 hrs. \n" ); document.write( "x/60 + (280-x)/10 = 8 \n" ); document.write( "Multiply thru by 60 to get:\r \n" ); document.write( "\n" ); document.write( "x + 6(280-x) = 480 \n" ); document.write( "-5x = 480 - 6*280\r \n" ); document.write( "\n" ); document.write( "-5x = -1200 \n" ); document.write( "x = 240 miles (distance traveled at 60 mph) \n" ); document.write( "280-x = 40 miles (distance traveled at 10 mph) \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |