document.write( "Question 173578: Log(2x+1)+log(x-1)=log9 \n" ); document.write( "
Algebra.Com's Answer #128444 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Log(2x+1)+log(x-1)=log9\r \n" ); document.write( "\n" ); document.write( "log[(2x+1)(x-1)] = log9\r \n" ); document.write( "\n" ); document.write( "(2x+1)(x-1) = 9\r \n" ); document.write( "\n" ); document.write( "2x^2 - x -1 = 9\r \n" ); document.write( "\n" ); document.write( "2x^2 - x - 10 = 0\r \n" ); document.write( "\n" ); document.write( "2x^2 -5x + 4x - 10 = 0\r \n" ); document.write( "\n" ); document.write( "x(2x-5) + 2(2x-5) = 0 \n" ); document.write( "(2x-5)(x+2) = 0 \n" ); document.write( "Realistic answer: \n" ); document.write( "x = 5/2 \n" ); document.write( "------------- \n" ); document.write( "Comment: x=-2 is extraneous because it would make log(x+1) = log(-1) \n" ); document.write( "which has no meaning. \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |