document.write( "Question 173578: Log(2x+1)+log(x-1)=log9 \n" ); document.write( "
Algebra.Com's Answer #128444 by stanbon(75887)\"\" \"About 
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Log(2x+1)+log(x-1)=log9\r
\n" ); document.write( "\n" ); document.write( "log[(2x+1)(x-1)] = log9\r
\n" ); document.write( "\n" ); document.write( "(2x+1)(x-1) = 9\r
\n" ); document.write( "\n" ); document.write( "2x^2 - x -1 = 9\r
\n" ); document.write( "\n" ); document.write( "2x^2 - x - 10 = 0\r
\n" ); document.write( "\n" ); document.write( "2x^2 -5x + 4x - 10 = 0\r
\n" ); document.write( "\n" ); document.write( "x(2x-5) + 2(2x-5) = 0
\n" ); document.write( "(2x-5)(x+2) = 0
\n" ); document.write( "Realistic answer:
\n" ); document.write( "x = 5/2
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\n" ); document.write( "Comment: x=-2 is extraneous because it would make log(x+1) = log(-1)
\n" ); document.write( "which has no meaning.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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