document.write( "Question 173547: find a quadratic model for the set of values (-2,-15),(0,-3),(4,-27) \n" ); document.write( "
Algebra.Com's Answer #128418 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "-15=4A-2B+C...eq 1 \n" ); document.write( " \n" ); document.write( "-27=16A+4B+C..eq 3 \n" ); document.write( ": \n" ); document.write( "lets take C's value in eq 2 and plug it into eq 1 and 3 \n" ); document.write( ": \n" ); document.write( "4A-2B+(-3)=-15....eq (4)---->4A-2B=-12----mult by 2---->8A-4B=-24 \n" ); document.write( "16A+4B+(-3)=-27...eq (5)---->16A+4B=-24 \n" ); document.write( ": \n" ); document.write( "8A-4B=-24.....eq (4) revised \n" ); document.write( "16A+4B=-24....eq (5) revised \n" ); document.write( ": \n" ); document.write( "now lets solve by elimination after we multiplied eq 4 by 2 . Add eq 4 and 5 together and as you can see the B terms will be eliminated(-4B+4B=0) and we are left with \n" ); document.write( ":8A+16A=-24-24 \n" ); document.write( ": \n" ); document.write( "24A=-48 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "plug A's found value back into eq 4.--> 8(-2)-4B=-24 \n" ); document.write( ": \n" ); document.write( "-4b=-8 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "so \n" ); document.write( "since \n" ); document.write( " |