document.write( "Question 173447: a+2c+3E+2F=270
\n" ); document.write( "2a+b+2d+2f=240
\n" ); document.write( "3a+4b+c+f=360
\n" ); document.write( "a+5c+2e=440
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Algebra.Com's Answer #128324 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
a+2c+3E+2F=270
\n" ); document.write( "2a+b+2d+2f=240
\n" ); document.write( "3a+4b+c+f=360
\n" ); document.write( "a+5c+2e=440
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\n" ); document.write( "Even assuming the E is the same as e, and F is f, you have 4 equations in 6 unknowns. That is not sufficient. You have to have 6 eqns if there are 6 unknowns.
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