document.write( "Question 173454: Not sure if this is the appropiate topic but.
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document.write( "A motorboat travels 325km in 5 hours going upstream and 534 km in 6 hours going downstream. What is the speed of the boat in still water and what is the speed of the current? I don't understand this. How can still water have a speed? I am totally lost. Van you help me figure this out? Thanks, Judy \n" );
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Algebra.Com's Answer #128313 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A motorboat travels 325km in 5 hours going upstream and 534 km in 6 hours going downstream. What is the speed of the boat in still water and what is the speed of the current? \n" ); document.write( "-------- \n" ); document.write( "It is not still water; it is moving water, or current. \n" ); document.write( "-------- \n" ); document.write( "Upstream DATA: \n" ); document.write( "distance = 325 km ; time = 5 hrs; rate = d/t = 325/5 = 65 km/h \n" ); document.write( "------------------ \n" ); document.write( "Downstream DATA; \n" ); document.write( "distance = 534 km ; time = 6 hrs ; rate = d/t = 534/6 = 267/3 = 89 km/h \n" ); document.write( "----------------------------------- \n" ); document.write( "EQUATIONS: \n" ); document.write( "b + c = 89 \n" ); document.write( "b - c = 65 \n" ); document.write( "--------------- \n" ); document.write( "Add to solve for b: (b is the speed of the boat in still water) \n" ); document.write( "2b = 154 \n" ); document.write( "b = 77 km/h (speed of the boat in still water) \n" ); document.write( "------------ \n" ); document.write( "If b+c = 89 then c = 12 km/h (speed of the current) \n" ); document.write( "====================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |