document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173433>Question 173433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four numbers have a total of 92. The first number is twice the second number and the third number is 4 more than the sum of the first two. The fourth number is 3 less than the difference of the first two numbers. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128290 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the four numbers be a, b, c, and d.<BR>\n" );
document.write( "From the problem description you can write:<BR>\n" );
document.write( "1) a+b+c+d = 92 \"The four numbers have a total of 92\"<BR>\n" );
document.write( "2) a = 2b \"The first number is twice the second number...\"<BR>\n" );
document.write( "3) c = (a+b)+4 \"...the third number is 4 more than the sum of the first two.\"<BR>\n" );
document.write( "4) d = (a-b)-3 \"The fourth number is 3 less than the difference of the first two numbers.\"<BR>\n" );
document.write( "Substitute equation 2) into equation 1) to get:<BR>\n" );
document.write( "1a) 2b+b+c+d = 92 Simplify.<BR>\n" );
document.write( "2a) 3b+c+d = 92 Now substitute equation 3 into this equation.<BR>\n" );
document.write( "2b) 3b+(a+b)+4+d = 92 Simplify this.<BR>\n" );
document.write( "2b) a+4b+d+4 = 92 Substitute equation 2) into this equation.<BR>\n" );
document.write( "2c) 2b+4b+d+4 = 94 Simplify.<BR>\n" );
document.write( "2c) 6b+d+4 = 92 Substitute equation 4) into this equation.<BR>\n" );
document.write( "2d) 6b+((a-b)-3)+4 = 92 Substitute equation 2) into this equation.<BR>\n" );
document.write( "2e) 6b+((2b-b)-3)+4 = 92 Simplify.<BR>\n" );
document.write( "2e) 7b+1 = 92 Subtract 1 from both sides.<BR>\n" );
document.write( "7b = 91 Divide both sides by 7.<BR>\n" );
document.write( "b = 13<BR>\n" );
document.write( "a = 2b = 2(13) = 26<BR>\n" );
document.write( "c = (a+b)+4 = 26+13+4 = 43<BR>\n" );
document.write( "d = (a-b)-3 = 26-13-3 = 10<BR>\n" );
document.write( "The numbers are:<BR>\n" );
document.write( "a = 26<BR>\n" );
document.write( "b = 13<BR>\n" );
document.write( "c = 43<BR>\n" );
document.write( "d = 10<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );