document.write( "Question 173427: Solve the equation:
\n" ); document.write( "logx27=2/3
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Algebra.Com's Answer #128286 by Alan3354(69443)\"\" \"About 
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Solve the equation:
\n" ); document.write( "logx27=2/3
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\n" ); document.write( "Assuming x is the base:
\n" ); document.write( "Put it into exponential form
\n" ); document.write( "\"x%5E%282%2F3%29+=+27\"
\n" ); document.write( "\"x%5E2+=+27%5E3\"
\n" ); document.write( "\"x+=+sqrt%2827%5E3%29\"
\n" ); document.write( "\"x+=+27%2Asqrt%2827%29\"
\n" ); document.write( "\"x+=+81%2Asqrt%283%29\"\r
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