document.write( "Question 173419: solve for x: 2x to the 2nd power minus 3x minus 1=0 \n" ); document.write( "
Algebra.Com's Answer #128283 by checkley77(12844)\"\" \"About 
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2x^2-3x-1=0
\n" ); document.write( "Using the quadratic equation:\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" we get:
\n" ); document.write( "x=(3+-sqrt[-362-4*2*-1])/2*2
\n" ); document.write( "x=(3+-sqrt[9+8])/4
\n" ); document.write( "x=(3+-sqrt17)/4
\n" ); document.write( "x=(3+-4.1231)/4
\n" ); document.write( "x=(3+4.1231)/4
\n" ); document.write( "x=7.1231/4
\n" ); document.write( "x=1.78 ans.
\n" ); document.write( "x=(3-4.1231)/4
\n" ); document.write( "x=-1.1231/4
\n" ); document.write( "x=.28 ans.
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