document.write( "Question 173419: solve for x: 2x to the 2nd power minus 3x minus 1=0 \n" ); document.write( "
Algebra.Com's Answer #128283 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 2x^2-3x-1=0 \n" ); document.write( "Using the quadratic equation: \n" ); document.write( "x=(3+-sqrt[-362-4*2*-1])/2*2 \n" ); document.write( "x=(3+-sqrt[9+8])/4 \n" ); document.write( "x=(3+-sqrt17)/4 \n" ); document.write( "x=(3+-4.1231)/4 \n" ); document.write( "x=(3+4.1231)/4 \n" ); document.write( "x=7.1231/4 \n" ); document.write( "x=1.78 ans. \n" ); document.write( "x=(3-4.1231)/4 \n" ); document.write( "x=-1.1231/4 \n" ); document.write( "x=.28 ans. \n" ); document.write( " \n" ); document.write( " |