document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173425>Question 173425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a perpendicular line 2x+5y=1 containing points (-1,2)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128275 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a perpendicular line 2x+5y=1 containing points (-1,2) <BR>\n" );
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document.write( "Find the slope, m, of line 2x+5y=1 by putting it into slope-intercept form.<BR>\n" );
document.write( "2x+5y=1<BR>\n" );
document.write( "5y = -2x + 1<BR>\n" );
document.write( "y = (-2/5)x + 1/5<BR>\n" );
document.write( "m = -2/5.  Lines perpendicular to it will have the negative inverse slope, +5/2<BR>\n" );
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document.write( "y-y1 = m*(x-x1) where (x1,y1) is the point (-1,2)<BR>\n" );
document.write( "y - 2 = (5/2)*(x + 1)<BR>\n" );
document.write( "y-2 = (5/2)x + 5/2<BR>\n" );
document.write( "y = (5/2)x + 9/2  slope-intercept form<BR>\n" );
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document.write( "2y = 5x + 9<BR>\n" );
document.write( "5x - 2y = -9 standard form\r<BR>\n" );
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