document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173407>Question 173407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	When two-thirds of a number is added to one-fourth of the same number, the result is 8 more than the original number. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128265 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The unknown number is x\r<BR>\n" );
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document.write( "The equation to solve is\r<BR>\n" );
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document.write( "2/3x+1/4x=x+8\r<BR>\n" );
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document.write( "The lcd is 12\r<BR>\n" );
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document.write( "Therefore multiply each term by 12\r<BR>\n" );
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document.write( "8x+3x=12x+96\r<BR>\n" );
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document.write( "simplfy terms\r<BR>\n" );
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document.write( "11x=12x+96\r<BR>\n" );
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document.write( "Subtract 12x from both sides\r<BR>\n" );
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document.write( "-x=96 \r<BR>\n" );
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document.write( "divide both sides by -1\r<BR>\n" );
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document.write( "x=-96\r<BR>\n" );
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document.write( "Let's doublecheck our answer\r<BR>\n" );
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document.write( "(2(-96)/3} +(-96/4)=-96+8\r<BR>\n" );
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document.write( "-64-24=-88 </SPAN>\n" );
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