document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173410>Question 173410</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321269470/algebrahomeworkh>Introductory Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation\r<BR>\n" );
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document.write( "x(x-3) = 40 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128260 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x(x-3) = 40\r<BR>\n" );
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document.write( "Expand the equation\r<BR>\n" );
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document.write( "x^2-3X=40\r<BR>\n" );
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document.write( "subtract 40 from both sides\r<BR>\n" );
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document.write( "x^2-3X-40=0\r<BR>\n" );
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document.write( "Find possible factors for 40\r<BR>\n" );
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document.write( "(40,1) (2,20) (8,5)\r<BR>\n" );
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document.write( "We see that the 40 has a negative sign which means that one of the factors is negative.\r<BR>\n" );
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document.write( "Then we find which two factors when added together can give you -3\r<BR>\n" );
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document.write( "I can see from the list that the only possible answer is 5,8\r<BR>\n" );
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document.write( "(x-8)(x+5)=0 is the factored form of the above equation\r<BR>\n" );
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document.write( "Therefore the answers are x=8 and x=-5 </SPAN>\n" );
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