document.write( "Question 173399: Factor the quadratic equation.
\n" ); document.write( " $\"+5x%5E2-19x-4+\"$
\n" ); document.write( "Like my last question, I don't understand how one can get the factors of -4 and then find the sum of -19 with those factors. \n" ); document.write( "

Algebra.Com's Answer #128245 by Mathtut(3670) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"5x%5E2-19x-4\"$ you must start with the factors that you know
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\n" ); document.write( " in the first terms of the factoring you have a combo of 5x and x as choices. In the second terms you have 1 and 4 as the possibles......so we need to maneuver those to meet our goal the middle term of -19x which always comes from a combination of the o and i(the outside and inside terms) in foil(first,outside,inside,last)
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\n" ); document.write( " $\"%285x%2B1%29%28x-4%29\"$ ...... the 5x has to be combined with the 4 while the x is combined with the one.....so as to get that -19x ( the outside(o) term is 5x(-4) and the inside(i) term is 1(x))... you must remember when you have a coefficient larger than 1 in the squared term it makes it more of a guessing game...This one is rather simple because there arent that many choices......Ther first terms are usually pretty easy....but sometimes the second terms can have multiple combinations to test.
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\n" ); document.write( " $\"system%28x=4%2Cx=-1%2F5%29\"$ \n" ); document.write( "

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