document.write( "Question 173211: A rectangular piece of metal 32cm by 22cm, has a square of side X cm removed from each corner in order to form a rectangular box. If the volume of the box is to be a maximum what is the value of X? \n" ); document.write( "
Algebra.Com's Answer #128222 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A rectangular piece of metal 32cm by 22cm, has a square of side X cm removed \n" ); document.write( " from each corner in order to form a rectangular box. \n" ); document.write( "If the volume of the box is to be a maximum what is the value of X? \n" ); document.write( ": \n" ); document.write( "From the given information we know the dimensions (L,W,H) of the box is: \n" ); document.write( "(32-2x) by (22-2x) by x \n" ); document.write( ": \n" ); document.write( "Area = length * width * height \n" ); document.write( "A = (32-2x) * (22 - 2x) * x \n" ); document.write( "FOIL \n" ); document.write( "A = x(704 - 64x - 44x + 4x^2) \n" ); document.write( "A = x(704 - 108x + 4x^2) \n" ); document.write( "A = 704x - 108x^2 + 4x^3 \n" ); document.write( "or the standard arrangement is: \n" ); document.write( "y = 4x^3 - 108x^2 + 704x \n" ); document.write( ": \n" ); document.write( "Plot this equation, we only are interested in the positive values x,y values \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Using my trusty Ti83, max volume occurs when x = 4.274 cm about 1348 cu/cm\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |