document.write( "Question 24135: How many pounds of coffee beans selling for $2.00 per pound should be mixed with 6 pounds of coffee beans selling for $2.80 per pound to obtain a mixture selling for $2.48 per pound. \n" ); document.write( "

Algebra.Com's Answer #12821 by Earlsdon(6294) $\"\"$ $\"About$

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Let x = the number of lbs of coffee selling for $2.00/lb. You want to mix x lbs of $2.00 coffee beans with 6 lbs of $2.80 coffee beans to obtain a mixture of (6+x) lbs of $2.48 coffee beans. Let's set up the appropriate equation to solve this mystery: \r
\n" ); document.write( "\n" ); document.write( " $\"x%282%29+%2B+6%282.8%29+=+%286%2Bx%29%282.48%29\"$ Simplify and solve for x.
\n" ); document.write( " $\"2x+%2B+16.8+=+14.88+%2B+2.48x\"$ Subtract 2x from both sides of the equation.
\n" ); document.write( " $\"16.8+=+14.88+%2B+0.48x\"$ Subtract 14.88 from both sides.
\n" ); document.write( " $\"1.92+=+0.48x\"$ Finally, divide both sides by 0.48
\n" ); document.write( " $\"1.92%2F0.48+=+x\"$
\n" ); document.write( " $\"x+=+4\"$ \r
\n" ); document.write( "\n" ); document.write( "You will need to mix 4 lbs of the $2.00 coffee beans with 6 lbs of the $2.80 coffee beans to obtain 10 lbs of $2.48 coffee bean mixture.
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