document.write( "Question 173354This question is from textbook intro algebra
\n" ); document.write( ": this algebra stuff is so confusing to me. I have a word problem that I don't know how to set up and solve.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is approximately 1.6 times the width. Find the dimensions of the rectangle is its are is 9000m^2
\n" ); document.write( "

Algebra.Com's Answer #128202 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangle is approximately 1.6 times the width. Find the dimensions of the rectangle is its are is 9000m^2
\n" ); document.write( "-----------
\n" ); document.write( "There is no need to be confused.
\n" ); document.write( "1st draw the picture of a rectangle
\n" ); document.write( "2nd label the width as \"x\" and the length as \"1.6x\"
\n" ); document.write( "3rd label the inside (area) as 9000m^2
\n" ); document.write( "-------------------
\n" ); document.write( "4th: write the equation for area: A = (length)(width)
\n" ); document.write( "5th: substitute what you know for the words
\n" ); document.write( "9000 = 1.6x*x
\n" ); document.write( "6th solve for \"x\"
\n" ); document.write( "1.6x^2 = 9000
\n" ); document.write( "x^2 = 9000/1.6
\n" ); document.write( "x^2 = 5625
\n" ); document.write( "x = 75 meters (width)
\n" ); document.write( "1.6x = 120 meters (length)
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );