document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173320>Question 173320</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8.	The area of a triangle is 13.5 square meters. Find the base and height of the rectangle if its height is 6 meters greater than its base. Use an equation and the formula ® area of a triangle = 0.5(base)(height). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #128155 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=128155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the base be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, then the height is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B6 ALIGN=MIDDLE  ALT=\"x%2B6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Since the area is given by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=bh%2F2 ALIGN=MIDDLE  ALT=\"A=bh%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, you can just substitute:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=13.5=%28x%28x%2B6%29%29%2F2 ALIGN=MIDDLE  ALT=\"13.5=%28x%28x%2B6%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Distribute, collect like terms, and put the equation into standard form for a quadratic:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=27=x%5E2%2B6x ALIGN=MIDDLE  ALT=\"27=x%5E2%2B6x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B6x-27=0 ALIGN=MIDDLE  ALT=\"x%5E2%2B6x-27=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Solve this by factoring, recognizing that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2A9=-27 ALIGN=MIDDLE  ALT=\"-3%2A9=-27\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2B9=6 ALIGN=MIDDLE  ALT=\"-3%2B9=6\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "One of your roots will be a negative value.  Exclude that root because it is extraneous introduced by the act of squaring the variable.  The other root will be the length of the base. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );