document.write( "Question 173315This question is from textbook Saxon Algebra 2
\n" );
document.write( ": Solve
\n" );
document.write( " 3x+2y=-6
\n" );
document.write( "-2x+5y=23
\n" );
document.write( "and classify the system \n" );
document.write( "
Algebra.Com's Answer #128153 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! 3x+2y=-6....eq 1 \n" ); document.write( "-2x+5y=23....eq 2\r \n" ); document.write( "\n" ); document.write( "lets use the process of elimination which means we need to manipulate eq 1 and 2 such that one of the variables is eliminated. There are various numbers we could multiply by the equations to reach this objective. Lets multiply eq 1 by 5 and eq 2 by -2 so that the y terms will be eliminated \n" ); document.write( ": \n" ); document.write( "15x+10y=-30...revised eq 1 \n" ); document.write( " 4x-10y=-46....revised eq 2 \n" ); document.write( ": \n" ); document.write( "now observing the equations we can see that when the equations are added to one another that the y terms are eliminated 10y-10y=0. We are left with \n" ); document.write( "15x+4x=-30-46 \n" ); document.write( ": \n" ); document.write( "19x=-76 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "now we take x's found value and plug it back into any equation to find y's value. I choose eq 1 \n" ); document.write( ": \n" ); document.write( "3(-4)+2y=-6 \n" ); document.write( ": \n" ); document.write( "-12+2y=-6 \n" ); document.write( ": \n" ); document.write( "2y=6 \n" ); document.write( ": \n" ); document.write( " |