document.write( "Question 173063: When Sara changes jobs, she rolledover $8480.00 in her retirement account into 2 simple interest accounts. on 1 account the annual simple interest rate is 8.25%, the 2nd account has annual simple interest rate is 5%. How much must be invested in each account if the 2 accounts earned the same amount of annual interest? \n" ); document.write( "

Algebra.Com's Answer #128126 by Mathtut(3670) $\"\"$ $\"About$

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lets call the amount invested in account 1, x and in account 2, y=(8400-x).
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\n" ); document.write( "account 1-----> .0825(x)
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\n" ); document.write( "account 2-----> .05(8480-x)
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\n" ); document.write( "we set these two formula's equal to each other to determine the amounts at which account 1 and account 2 will be equal.
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\n" ); document.write( ".0825x=.05(8480-x)
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\n" ); document.write( ".0825x=424-.05x
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\n" ); document.write( ".1325x=424
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\n" ); document.write( " $\"highlight%28x=3200%29\"$ amount invested at 8.25%
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\n" ); document.write( " $\"highlight%28y=8480-3200=5280%29\"$ amount invested at 5%
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