document.write( "Question 173293: how do you solve this problem
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Algebra.Com's Answer #128121 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2B4%29%2F2=%28x-3%29%2F3\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"6%28%28x%2B4%29%2Fcross%282%29%29=6%28%28x-3%29%2Fcross%283%29%29\" Multiply both sides by the LCD 6 to clear the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B4%29=2%28x-3%29\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B12=2x-6\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=2x-6-12\" Subtract \"12\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x-2x=-6-12\" Subtract \"2x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=-6-12\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=-18\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=-18\"
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