document.write( "Question 173277: The numbe of people who hear a rumor increases exponentially. If 20 people start a rumor and if each person who hears the rumor repeats it to two people a day, the number of people N who have heard the rumor after t days is given by the function.
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document.write( "N(t)=20(3)^t
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document.write( "a. How many people have heard the rumor after 5 days?
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document.write( "b. After what amount of time will 1000 people have heard the rumor?
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document.write( "c. What is the doubling time for the number of people who have heard the rumor?\r
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Algebra.Com's Answer #128102 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The numbe of people who hear a rumor increases exponentially. If 20 people start a rumor and if each person who hears the rumor repeats it to two people a day, the number of people N who have heard the rumor after t days is given by the function N(t) = 20(3)^t \n" ); document.write( "a. How many people have heard the rumor after 5 days? \n" ); document.write( "N(5) = 20*3^5 = 4860 \n" ); document.write( "------------------------------------ \n" ); document.write( "b. After what amount of time will 1000 people have heard the rumor? \n" ); document.write( "1000=20*3^t \n" ); document.write( "50 = 3^t \n" ); document.write( "tlog(3) = log50 \n" ); document.write( "t = log(50)/log(30 \n" ); document.write( "t = 3.56 days \n" ); document.write( "============================= \n" ); document.write( "c. What is the doubling time for the number of people who have heard the rumor? \n" ); document.write( "N(t) = 20*3^t \n" ); document.write( "40 = 20*3^t \n" ); document.write( "2 = 3^t \n" ); document.write( "tlog(3) = log(2)\r \n" ); document.write( "\n" ); document.write( "t = log(2)/log(3) \n" ); document.write( "t = 0.631 days \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |