document.write( "Question 173176This question is from textbook
\n" ); document.write( ": I need help I'm coming up with crazy answer can you be nice to show me step by step It will really help me alot thank you.\r
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\n" ); document.write( "\n" ); document.write( "A cell divides into two identical copies every 4 minutes. How many cells will exist after 3 hours?
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Algebra.Com's Answer #128036 by Earlsdon(6294)\"\" \"About 
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Try this!
\n" ); document.write( "Starting with one cell at time zero and doubling every 4 minutes:
\n" ); document.write( "Time-----------Cells
\n" ); document.write( "..0(4).........1 --> \"2%5E0+=+1\"
\n" ); document.write( "..1(4).........2 --> \"2%5E1+=+2\"
\n" ); document.write( "..2(4).........4 --> \"2%5E2+=+4\"
\n" ); document.write( "..3(4).........8 --> \"2%5E3+=+8\"
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\n" ); document.write( "..45(4).........\"2%5E45\"\r
\n" ); document.write( "\n" ); document.write( "So you need to know how many times this doubling will take place in 3 hours. Divide 3 hours, that's 180 minutes by 4 to get 45 times, (n = 45) so at the end of 3 hours, there will be \"highlight%282%5E45+=+35184372088832%29\" cells.
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