document.write( "Question 173103: The length of a rectangular park is 2 times greater than its width.\r
\n" ); document.write( "\n" ); document.write( "The park is framed by sidewalk that is 2 m wide.\r
\n" ); document.write( "\n" ); document.write( "The area of the park is increased by 136m square if the sidewalk is included.\r
\n" ); document.write( "\n" ); document.write( "What is the area of the park without the surrounding sidewalk ?\r
\n" ); document.write( "\n" ); document.write( "Show the work.
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Algebra.Com's Answer #127943 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
L=2W
\n" ); document.write( "AREA OF PARK=LW
\n" ); document.write( "AREA OF PARK=2W*W=2W^2
\n" ); document.write( "AREA WITH SIDEWALK=(2W+2*2)(W+2*2)
\n" ); document.write( "AREA WITH SIDEWALK=(2W+4)(W+4)
\n" ); document.write( "AREA WITH SIDEWALK=2W^2+12W+16
\n" ); document.write( "(2W^2+12W+16)-(2W^2)=136
\n" ); document.write( "12W=136-16
\n" ); document.write( "12W=120
\n" ); document.write( "W=10 M.
\n" ); document.write( "L=2*10=20 M.
\n" ); document.write( "PROOF:
\n" ); document.write( "20*10=200 M^2 FOR THE PARK
\n" ); document.write( "(20+4)(10+4)=200+136 M^2 FOR THE PARK PLUS THE SIDEWALK.
\n" ); document.write( "24*14=336
\n" ); document.write( "336=336\r
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