document.write( "Question 173103: The length of a rectangular park is 2 times greater than its width.\r
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document.write( "The park is framed by sidewalk that is 2 m wide.\r
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document.write( "The area of the park is increased by 136m square if the sidewalk is included.\r
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document.write( "What is the area of the park without the surrounding sidewalk ?\r
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document.write( "Show the work.
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Algebra.Com's Answer #127942 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The length of a rectangular park is 2 times greater than its width. \n" ); document.write( "The park is framed by sidewalk that is 2 m wide. \n" ); document.write( "The area of the park is increased by 136m square if the sidewalk is included. \n" ); document.write( "What is the area of the park without the surrounding sidewalk ? \n" ); document.write( ". \n" ); document.write( "area of sidewalk is 136 sq m \n" ); document.write( ". \n" ); document.write( "\"area of park plus walk\" is \n" ); document.write( ". \n" ); document.write( "Park measurements: \n" ); document.write( "Let w = width of park \n" ); document.write( "then \n" ); document.write( "2w = length of park \n" ); document.write( ". \n" ); document.write( "Park plus walk measurements: \n" ); document.write( "w+4 = width \n" ); document.write( "2w+4 = length \n" ); document.write( ". \n" ); document.write( "(w+4)(2w+4) - w(2w) = 136 \n" ); document.write( "2w^2+4w+8w+16 - 2w^2 = 136 \n" ); document.write( "4w+8w+16 = 136 \n" ); document.write( "12w+16 = 136 \n" ); document.write( "12w = 120 \n" ); document.write( "w = 10 m (width) \n" ); document.write( ". \n" ); document.write( "Length: \n" ); document.write( "2w = 2(10) = 20 m(length) \n" ); document.write( " \n" ); document.write( " |