document.write( "Question 173103: The length of a rectangular park is 2 times greater than its width.\r
\n" ); document.write( "\n" ); document.write( "The park is framed by sidewalk that is 2 m wide.\r
\n" ); document.write( "\n" ); document.write( "The area of the park is increased by 136m square if the sidewalk is included.\r
\n" ); document.write( "\n" ); document.write( "What is the area of the park without the surrounding sidewalk ?\r
\n" ); document.write( "\n" ); document.write( "Show the work.
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Algebra.Com's Answer #127942 by nerdybill(7384)\"\" \"About 
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The length of a rectangular park is 2 times greater than its width.
\n" ); document.write( "The park is framed by sidewalk that is 2 m wide.
\n" ); document.write( "The area of the park is increased by 136m square if the sidewalk is included.
\n" ); document.write( "What is the area of the park without the surrounding sidewalk ?
\n" ); document.write( ".
\n" ); document.write( "area of sidewalk is 136 sq m
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\n" ); document.write( "\"area of park plus walk\" is
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\n" ); document.write( "Park measurements:
\n" ); document.write( "Let w = width of park
\n" ); document.write( "then
\n" ); document.write( "2w = length of park
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\n" ); document.write( "Park plus walk measurements:
\n" ); document.write( "w+4 = width
\n" ); document.write( "2w+4 = length
\n" ); document.write( ".
\n" ); document.write( "(w+4)(2w+4) - w(2w) = 136
\n" ); document.write( "2w^2+4w+8w+16 - 2w^2 = 136
\n" ); document.write( "4w+8w+16 = 136
\n" ); document.write( "12w+16 = 136
\n" ); document.write( "12w = 120
\n" ); document.write( "w = 10 m (width)
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\n" ); document.write( "Length:
\n" ); document.write( "2w = 2(10) = 20 m(length)
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