document.write( "Question 173087: Find the standard form of the equation of the line that passes through the points (0, -1) and (8, 8). \n" ); document.write( "
Algebra.Com's Answer #127916 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "First let's find the slope of the line through the points and \r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula.\r
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\n" ); document.write( "\n" ); document.write( "\"m=%288--1%29%2F%288-0%29\" Plug in \"y%5B2%5D=8\", \"y%5B1%5D=-1\", \"x%5B2%5D=8\", and \"x%5B1%5D=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%289%29%2F%288-0%29\" Subtract \"-1\" from \"8\" to get \"9\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%289%29%2F%288%29\" Subtract \"0\" from \"8\" to get \"8\"\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line that goes through the points and is \"m=9%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula:\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y--1=%289%2F8%29%28x-0%29\" Plug in \"m=9%2F8\", \"x%5B1%5D=0\", and \"y%5B1%5D=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B1=%289%2F8%29%28x-0%29\" Rewrite \"y--1\" as \"y%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B1=%289%2F8%29x-%289%2F8%29%280%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B1=%289%2F8%29x-0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B1=%289%2F8%29x\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"y-%289%2F8%29x=-1\" Subtract \"%289%2F8%29x\" from both sides. Subtract 1 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-%289%2F8%29x%2By=-1\" Rearrange the terms. \r
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\n" ); document.write( "\n" ); document.write( "\"-9x%2B8y=-8\" Multiply EVERY term by the LCD 8 to clear the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"9x-8y=8\" Multiply EVERY term by -1 to make the \"x\" coefficient positive.\r
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\n" ); document.write( "\n" ); document.write( "So now the equation is in standard form \"Ax%2BBy=C\" where \"A=9\", \"B=-8\", and \"C=8\"
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