document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=173021>Question 173021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> show that p(-5/7,-2sqrt(6)/7) is on the unit circle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127893 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> show that p(-5/7,-2sqrt(6)/7) is on the unit circle<BR>\n" );
document.write( "r^2 = (5/7)^2 + (2sqrt(6)/7)^2<BR>\n" );
document.write( "= 25/49 + 4*6/49<BR>\n" );
document.write( "= 49/49<BR>\n" );
document.write( "= 1<BR>\n" );
document.write( "radius = 1, so it's on the circle.\r<BR>\n" );
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