document.write( "Question 172999: For the exponential function e^x and logarithmic function log x, graphically show the effect if x is doubled, can someone help me with the problem, I do not understand what they are asking. Thank you!!! \r
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Algebra.Com's Answer #127869 by gonzo(654)\"\" \"About 
You can put this solution on YOUR website!
they want to know the impact of doubling x.
\n" ); document.write( "i take this to mean:
\n" ); document.write( "if you have \"e%5Ex\" and you double x, then you have \"e%5E%282x%29\"
\n" ); document.write( "likewise:
\n" ); document.write( "if you have \"log%2810%2Cx%29\" and you double x, then you have \"log%2810%2C2x%29\"
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\n" ); document.write( "first i will graph \"e%5Ex\" and \"e%5E%282x%29\" to see what the impact would be:
\n" ); document.write( "look below the graph for further comments.
\n" ); document.write( "\"graph%28800%2C800%2C-3%2C5%2C-2%2C20%2C2.718281828%5Ex%2C2.718281828%5E%282x%29%29\"
\n" ); document.write( "the faster rising curve is \"e%5E%282x%29\"
\n" ); document.write( "when x = 0, the values of both curves is the same.
\n" ); document.write( "when x = 1, the value of \"e%5Ex\" is 2.718... and the value of \"e%5E%282x%29\" is 7.389...
\n" ); document.write( "when x = 2, the value of \"e%5Ex\" is 7.389... and the value of \"e%5E%282x%29\" is 54.598...
\n" ); document.write( "the value of \"e%5E2x\" appears to be the value of \"%28e%5Ex%29%5E2\" which is should since\"%28a%5Eb%29%5Ec\" equals \"a%5E%28b%2Ac%29\" by the laws of exponentiation.
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\n" ); document.write( "when x = -.5, \"e%5Ex\" = .6065 and \"e%5E%282x%29\" = .3678.
\n" ); document.write( "\".6065%5E2\" = .3678 so the ratio holds even though \"e%5E%282x%29\" is smaller than \"e%5Ex\" at this point.
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\n" ); document.write( "you can see this on the graph.
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\n" ); document.write( "the graph of \"log%2810%2Cx%29\" and \"log%2810%2C2x%29\" is shown now.
\n" ); document.write( "look below the graph for further comments.
\n" ); document.write( "\"graph%28800%2C800%2C-2%2C40%2C-1%2C2%2Clog%2810%2Cx%29%2Clog%2810%2C2x%29%29\"
\n" ); document.write( "this graph doesn't show such a dramatic change in the value of log(x) versus log(2x)
\n" ); document.write( "example:
\n" ); document.write( "when x = 10, log(x) = 1, and log(2x) = 1.301...
\n" ); document.write( "when x = 100, log(x) = 2, and log(2x) = 2.301...
\n" ); document.write( "when x = 1000, log(x) = 3, and log(2x) = 3.301...
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\n" ); document.write( "this is because when x is an exponent, it has a very large impact on the result.
\n" ); document.write( "when x is the result of exponentiation, it has a very small impact on the result.
\n" ); document.write( "when x is the exponent, this is what happens:
\n" ); document.write( "if you take x = 1, then 10^1 = 10
\n" ); document.write( "if you take x = 10, then 10^10 = 10000000000
\n" ); document.write( "there's a big difference.
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\n" ); document.write( "when x is the result of exponentiation, this is what happens:
\n" ); document.write( "if you take x = 1000, then 10^y = 1000 which means y = 3.
\n" ); document.write( "if you double x to be 2000, then 10^y = 2000 which means y = 3.301029996
\n" ); document.write( "doubling the answers causes a very small increase in the exponent.
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\n" ); document.write( "y = 10^x means x is the exponent
\n" ); document.write( "y = log(x) means x is the answer.
\n" ); document.write( "remember:
\n" ); document.write( "y = log(x) if and only if x = 10^y
\n" ); document.write( "x is the result of exponentiation when you say y = log(x)
\n" ); document.write( "x is the exponent itself when you say y = 10^x.
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\n" ); document.write( "best i can do.
\n" ); document.write( "hope it makes sense.
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