document.write( "Question 172875: 1/3 log 5 12x=2\r
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Algebra.Com's Answer #127847 by Alan3354(69443)\"\" \"About 
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1/3 log 5 12x=2
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\n" ); document.write( "If you mean \"%281%2F3%29log%285%2C12x%29+=+2\", then
\n" ); document.write( "\"log%285%2C%2812x%29%5E%281%2F3%29%29+=+2\"
\n" ); document.write( "\"%2812x%29%5E%281%2F3%29+=+25\"
\n" ); document.write( "12x = 15625
\n" ); document.write( "x = 15625/12\r
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