document.write( "Question 172988This question is from textbook algebra 1
\n" ); document.write( ": a ladder is 25ft long. the ladder needs to reach to a window that is 24ft above the ground.how far awayfrom the building should the bottom of the ladder be placed? \n" ); document.write( "
Algebra.Com's Answer #127841 by jim_thompson5910(35256)\"\" \"About 
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Let x=the distance from the bottom of the ladder to the building.\r
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\n" ); document.write( "\n" ); document.write( "We basically have this triangle set up:\r
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\n" ); document.write( "\n" ); document.write( "Since the legs are \"24\" and \"x\" this means that \"a=24\" and \"b=x\"\r
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\n" ); document.write( "\n" ); document.write( "Also, since the hypotenuse is \"25\", this means that \"c=25\".\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" Start with the Pythagorean theorem.\r
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\n" ); document.write( "\n" ); document.write( "\"24%5E2%2Bx%5E2=25%5E2\" Plug in \"a=24\", \"b=x\", \"c=25\" \r
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\n" ); document.write( "\n" ); document.write( "\"576%2Bx%5E2=25%5E2\" Square \"24\" to get \"576\".\r
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\n" ); document.write( "\n" ); document.write( "\"576%2Bx%5E2=625\" Square \"25\" to get \"625\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=625-576\" Subtract \"576\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=49\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2849%29\" Take the square root of both sides. Note: only the positive square root is considered (since a negative length doesn't make sense).\r
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\n" ); document.write( "\n" ); document.write( "\"x=7\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=7\".\r
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\n" ); document.write( "\n" ); document.write( "This means that the bottom of the ladder should be placed 7 ft from the building.
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