document.write( "Question 24085: I need to solve this equation by factoring. x^3+5x^2-6x=0? So far, i have (x^2-?)(x+?), but i don't quite understand the factoring part for this equation. Please help. \n" ); document.write( "

Algebra.Com's Answer #12783 by rapaljer(4671) $\"\"$ $\"About$

You can put this solution on YOUR website!
First factor out the common factor of x:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"+x%5E3%2B5x%5E2-6x=0\"$
\n" ); document.write( " $\"x%28x%5E2%2B5x-6%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%28x%2B6%29%28x-1%29+=+0\"$ \r
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\n" ); document.write( "\n" ); document.write( "Set each factor equal to zero. There will be three solutions:\r
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\n" ); document.write( "\n" ); document.write( "x= 0\r
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\n" ); document.write( "\n" ); document.write( "x+6= 0
\n" ); document.write( "x=-6\r
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\n" ); document.write( "\n" ); document.write( "x-1 = 0
\n" ); document.write( "x=1\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( " \n" ); document.write( "

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