document.write( "Question 172939This question is from textbook Introductory Algebra
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document.write( ": The current in a stream moves at a speed of 3 mph. A boat travels 45 mi upstream and 45 mi downstream in a total time of 8 hr. What is the speed of the boat in still water? \n" );
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Algebra.Com's Answer #127811 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The current in a stream moves at a speed of 3 mph. A boat travels 45 mi upstream and 45 mi downstream in a total time of 8 hr. What is the speed of the boat in still water? \n" ); document.write( ". \n" ); document.write( "You will need to apply the \"distance\" formula: \n" ); document.write( "d = rt \n" ); document.write( "where \n" ); document.write( "d is distance \n" ); document.write( "r is rate or speed \n" ); document.write( "t is time \n" ); document.write( ". \n" ); document.write( "Solving for t: \n" ); document.write( "d = rt \n" ); document.write( "d/r = t \n" ); document.write( ". \n" ); document.write( "Let x = speed of boat in still water \n" ); document.write( "45/(x+3) + 45/(x-3) = 8 \n" ); document.write( "Multiplying both sides by:(x+3)(x-3) \n" ); document.write( "45(x-3) + 45(x+3) = 8(x+3)(x-3) \n" ); document.write( "45[(x-3) + (x+3)] = 8(x^2-9) \n" ); document.write( "45[2x] = 8x^2-72 \n" ); document.write( "90x = 8x^2-72 \n" ); document.write( "0 = 8x^2-90x-72 \n" ); document.write( "0 = 4x^2-45x-36 \n" ); document.write( ". \n" ); document.write( "Since we can't factor, we solve with the quadratic equation. Doing so will yield: \n" ); document.write( "x = {12, -0.75} \n" ); document.write( ". \n" ); document.write( "We can ignore the negative solution leaving us with \n" ); document.write( "x = 12 mph (speed of boat in still waters) \n" ); document.write( ". \n" ); document.write( "Details of quadratic follows: \n" ); document.write( "
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