document.write( "Question 24078: will you please help me with this word problem. The area of a right triangle is 250in2.find the lengths of its legs if one leg is 5 inches longer than the other. \n" ); document.write( "
Algebra.Com's Answer #12778 by Paul(988)\"\" \"About 
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length No. 2= 5+x
\n" ); document.write( "Length no.1 = x\r
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\n" ); document.write( "\n" ); document.write( "area of right triangle = \"1%2F2+x+lw\"\r
\n" ); document.write( "\n" ); document.write( "\"250+=+x%285%2Bx%29%2F2\"
\n" ); document.write( "\"250+=+x%5E2%2B5x%2F2\"
\n" ); document.write( "\"250%282%29=x%5E2%2B5x\"
\n" ); document.write( "\"500=x%5E2%2B5x\"
\n" ); document.write( "\"x%5E2%2B5x-500=0\"
\n" ); document.write( "Use quadratic Forumla: \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "in \"ax%5E2%2Bbx%2Bc\" a= 1, b = 5 and c=-500\r
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\n" ); document.write( "\n" ); document.write( "\"x+=-5+%2B-+sqrt%28%285%292-4%281%29%28-500%29%29%2F+2%2A1%29\"
\n" ); document.write( "\"x=-5%2B-sqrt%2825%2B2000%29%29%2F+2%29\"
\n" ); document.write( "\"x=-5%2B-sqrt%282025%29%29%2F+2%29\"
\n" ); document.write( "Add:
\n" ); document.write( "\"x=-5%2B45%2F%282%29\"
\n" ); document.write( "x=20\r
\n" ); document.write( "\n" ); document.write( "20+5=25
\n" ); document.write( "And \"20+x+25%2F%282%29\"
\n" ); document.write( "=250\r
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\n" ); document.write( "\n" ); document.write( "Hence the one side of the right triangle is 20cm and the other side is 25 cm.
\n" ); document.write( "Paul.
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