document.write( "Question 172880: How do you write y=-(x+1)^2-2 in standard and graph it? \n" ); document.write( "
Algebra.Com's Answer #127760 by midwood_trail(310)\"\" \"About 
You can put this solution on YOUR website!
You were given the parabola in vertex form.\r
\n" ); document.write( "\n" ); document.write( "You need to express it in standard form.\r
\n" ); document.write( "\n" ); document.write( "The standard form is y = ax^2 + bx + c\r
\n" ); document.write( "\n" ); document.write( "Your equation: y = -(x+1)^2 - 2\r
\n" ); document.write( "\n" ); document.write( "y = -(x+1)(x+1) - 2\r
\n" ); document.write( "\n" ); document.write( "y = -(x^2 + 2x + 1) - 2\r
\n" ); document.write( "\n" ); document.write( "y = -x^2 - 2x - 1 - 2\r
\n" ); document.write( "\n" ); document.write( "y = -x^2 - 2x - 3\r
\n" ); document.write( "\n" ); document.write( "=======================\r
\n" ); document.write( "\n" ); document.write( "Since the x^2 term has a negative infront, this means the parabola will be graphed downward (like an up side down letter U) and will have maximum value at the vertex.\r
\n" ); document.write( "\n" ); document.write( "To graph, select 3 negative and 3 positive values for x, simplify to find y values that together will make 6 points in the form (x,y). When you have the 6 points, plot them on the xy-plane and then connect each point with a smooth downward curve.\r
\n" ); document.write( "\n" ); document.write( "Understand?\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );