document.write( "Question 172883: Solve by completing the square.
\n" ); document.write( "x² = 5x + 2
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Algebra.Com's Answer #127754 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Step 1: Arrange your equation so that the variables are on the left and the constant term is on the right:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=5x%2B2\" => \"x%5E2-5x=2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2: Divide both sides by the coefficient on the 2nd order term. In this case the coefficient is 1, so you can ignore this step.\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Divide the coefficient on the 1st order term by 2 and then square the result.\r
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\n" ); document.write( "\n" ); document.write( "\"%285%2F2%29%5E2=25%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4: Add the result of Step 3 to both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B5x%2B%2825%2F4%29=2%2B%2825%2F4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 5: You have now created a perfect square trinomial on the left. Factor it\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B%285%2F2%29%29%5E2=33%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Step 6: Take the square root of both sides remembering to consider both the positive and negative roots\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B%285%2F2%29=sqrt%2833%2F4%29\" or \"x%2B%285%2F2%29=-sqrt%2833%2F4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5B1%5D=%28-5%2Bsqrt%2833%29%29%2F2\" or \"x%5B2%5D=%28-5-sqrt%2833%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Those are the exact answers. You can use a calculator if you need numerical approximations
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