document.write( "Question 172883: Solve by completing the square.
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Algebra.Com's Answer #127752 by jim_thompson5910(35256)\"\" \"About 
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\"x%5E2=5x+%2B+2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-5x+=+2\" Subtract 5x from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the x coefficient 5 to get \"5%2F2\". Square that value to get \"25%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-5x+%2B25%2F4=+2%2B25%2F4\" Add \"25%2F4\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-5x+%2B25%2F4=+33%2F4\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-5%2F2%29%5E2+=33%2F4\" Factor \"x%5E2-5x+%2B25%2F4\" to get \"%28x-5%2F2%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-5%2F2=0%2B-sqrt%2833%2F4%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x-5%2F2=sqrt%2833%2F4%29\" or \"x-5%2F2=-sqrt%2833%2F4%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x-5%2F2=sqrt%2833%29%2F2\" or \"x-5%2F2=-sqrt%2833%29%2F2\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "\"x=5%2F2%2Bsqrt%2833%29%2F2\" or \"x=5%2F2-sqrt%2833%29%2F2\" Add \"5%2F2\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%285%2Bsqrt%2833%29%29%2F%282%29\" or \"x=%285-sqrt%2833%29%29%2F%282%29\" Combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=%285%2Bsqrt%2833%29%29%2F%282%29\" or \"x=%285-sqrt%2833%29%29%2F%282%29\".
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