document.write( "Question 172872: I tried these problems but I'm not sure if they're right. There were 3 parts, or 3 different equations to solve rather. part a) ln(x-4) + ln(2x) = ln(6). first i distributed the ln to the (x-4) and came up with ln(x) - ln(4) + ln(2x) = ln(6). I dont know if this is possible, but then i canceled out all of the lns and was left with 3x=10, meaning x=10/3.
\n" ); document.write( "partb) e^2x-7 = 9. I know you have to take the ln of each side, but then i got stuck after i put the exponent as the coefficient leaving me with 2x-7lne = ln9
\n" ); document.write( "partc) log (9x+5) - log3 =2. not sure how to do this one.
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Algebra.Com's Answer #127742 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, as they say in the old country...\"you can't that there 'ere\"
\n" ); document.write( "Let's see how it should go:
\n" ); document.write( "a) \"ln%28x-4%29%2Bln%282x%29+=+ln%286%29\" Apply the \"product rule\" for logarithms...\"log%28M%29%2Blog%28N%29+=+log%28M%2AN%29\"
\n" ); document.write( "\"ln%28%28x-4%29%282x%29%29+=+ln%286%29\" Simplify the left side.
\n" ); document.write( "\"ln%282x%5E2-8x%29+=+ln%286%29\" ...and if \"log%28M%29+=+log%28N%29\" then \"M+=+N\", so...
\n" ); document.write( "\"%282x%5E2-8x%29+=+6\" Subtract 6 from both sides.
\n" ); document.write( "\"2x%5E2-8x-6+=+0\" Solve by the quadratic formula:
\n" ); document.write( "\"x+=+%28-%28-8%29%2B-sqrt%28%28-8%29%5E2-4%282%29%28-6%29%29%29%2F2%282%29\"
\n" ); document.write( "\"x+=+%288%2B-sqrt%2864%2B48%29%29%2F4\"
\n" ); document.write( "\"x+=+%288%2B4sqrt%287%29%29%2F4\" or \"x+=+%288-2sqrt%287%29%29%2F4\"
\n" ); document.write( "\"x+=+2%2Bsqrt%287%29\" or \"x+=+2-sqrt%287%29\"
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "b) \"e%5E%282x-7%29+=+9\" Take the natural log of both sides.
\n" ); document.write( "\"ln%28e%5E%282x-7%29%29+=+ln%289%29\" Apply the \"power rule\" to the left side.
\n" ); document.write( "\"%282x-7%29ln%28e%29+=+ln%289%29\" Substitute \"ln%28e%29+=+1\"
\n" ); document.write( "\"2x-7+=+ln%289%29\" Evaluate the ln(9).
\n" ); document.write( "\"2x-7+=+2.197\" Add 7 to both sides.
\n" ); document.write( "\"2x+=+9.197\" Divide both sides by 2.
\n" ); document.write( "\"x+=+4.598\"
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "c)\"log%28%289x%2B5%29%29-log%283%29+=+2\" Apply the \"quotient rule\" to the left side.
\n" ); document.write( "\"log%28%289x%2B5%29%2F3%29+=+2\" Rewrite in exponential form.
\n" ); document.write( "\"10%5E2+=+%289x%2B5%29%2F3\" Multiply both sides by 3.
\n" ); document.write( "\"300+=+9x%2B5\" Subtract 5 from both sides.
\n" ); document.write( "\"295+=+9x\" Divide both sides by 9.
\n" ); document.write( "\"x+=+32.77\"
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