document.write( "Question 172872: I tried these problems but I'm not sure if they're right. There were 3 parts, or 3 different equations to solve rather. part a) ln(x-4) + ln(2x) = ln(6). first i distributed the ln to the (x-4) and came up with ln(x) - ln(4) + ln(2x) = ln(6). I dont know if this is possible, but then i canceled out all of the lns and was left with 3x=10, meaning x=10/3.
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document.write( "partb) e^2x-7 = 9. I know you have to take the ln of each side, but then i got stuck after i put the exponent as the coefficient leaving me with 2x-7lne = ln9
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document.write( "partc) log (9x+5) - log3 =2. not sure how to do this one. \n" );
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Algebra.Com's Answer #127742 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Well, as they say in the old country...\"you can't that there 'ere\" \n" ); document.write( "Let's see how it should go: \n" ); document.write( "a) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------------------------- \n" ); document.write( "b) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------------------------- \n" ); document.write( "c) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |