document.write( "Question 172849This question is from textbook
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document.write( ": How do you find the solutions of the equation sin2x + cos(x)=0 \n" );
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Algebra.Com's Answer #127714 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! sin2x + cos(x)=0 \n" ); document.write( "============= \n" ); document.write( "sin^2 = 1-cos^2 \n" ); document.write( "1-cos^2 + cos = 0 \n" ); document.write( "cos^2 - cos - 1 = 0 \n" ); document.write( "A quadratic in cos(x) \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "cos(x) = 1/2 + sqrt(5)/2 =~1.618 \n" ); document.write( "cos>1 is not a real number, so ignore it. \n" ); document.write( "------------------- \n" ); document.write( "cos(x) = 1/2 - sqrt(5)/2 =~ -0.618 \n" ); document.write( "x = 128.173º\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |