document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=172835>Question 172835</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What Would be The solution to these problems?<BR>\n" );
document.write( "1.Change -165.852 to degrees,minutes and second's<BR>\n" );
document.write( "2.Write 28 42' 13\" as a decimal to the nearest thousanth<BR>\n" );
document.write( "3.If a 570 angle is in standard position,etermine a coterminal angle that is beetween 0 and 360. State the quadrant or axis in which the terminal side lies.<BR>\n" );
document.write( "4.Find the value of cosine for angle A in a right triangle ABC if a=3 and b=6. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127697 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  The degrees part you can see by inspection, it is just the integer part of -165.852.  Then we have 0.852 left over.  Since there are 60 minutes in a degree, we should hav 0.852*60 degrees.  The calculator says:  51.12.  Take the integer part again to give you the number of minutes, 51.  Now ther is 0.12 left over.  There are 60 seconds in a minute, so we have 0.12*60 seconds.  Calculator says: 7.2.  Putting it all together -165.852° = -165° 51' 7.2\"\r<BR>\n" );
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document.write( "2.  Turn the process around.  28° 42' 13\"  13\" = (13/60)' or 0.217 (roughly) so that means we have 28° 42.217' But 42.217' = (42.217/60)° or 0.704 (again, roughly) so that means we have 28.704°\r<BR>\n" );
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document.write( "3.  Use integer division (the kind you first learned to do where you came up with a quotient and a remainder)  570°/360° = 1 r 210.  The remainder is the measure of the desired coterminal angle.  So 210° is the measure required.   Quadrant I is from 0° to 90°, Quadrant II is from 90° to 180°, Quadrant III is from 180° to 270°, and Quadrant IV is what is left.  180° < 210° < 270°, so your angle is in Quadrant III.\r<BR>\n" );
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document.write( "4. The first thing you need is the length of the hypotenuse of the triangle given by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=sqrt%28a%5E2%2Bb%5E2%29=sqrt%283%5E2%2B6%5E2%29=sqrt%2845%29=3%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"c=sqrt%28a%5E2%2Bb%5E2%29=sqrt%283%5E2%2B6%5E2%29=sqrt%2845%29=3%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Presuming your triangle is labled such that side <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b ALIGN=MIDDLE  ALT=\"b\"   DISABLED_style= \"max-width:90%; height:auto;\" > is adjacent angle A as is typical, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28A%29=b%2Fc=6%2F%283%2Asqrt%285%29%29=1%2F2sqrt%285%29 ALIGN=MIDDLE  ALT=\"cos%28A%29=b%2Fc=6%2F%283%2Asqrt%285%29%29=1%2F2sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  However, common practice dictates that you rationalize any denominators that contain radicals, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2sqrt%285%29%29%28%282sqrt%285%29%29%2F%282sqrt%285%29%29%29=2sqrt%285%29%2F20=sqrt%285%29%2F10 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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