document.write( "Question 172809: solve by graphing
\n" ); document.write( "x-y=1
\n" ); document.write( "x+y=-1
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Algebra.Com's Answer #127680 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Start with the given system of equations:\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x-y=1%2Cx%2By=-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "In order to graph these equations, we must solve for y first.\r
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\n" ); document.write( "\n" ); document.write( "Let's graph the first equation:\r
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\n" ); document.write( "\n" ); document.write( "\"x-y=1\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-y=1-x\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281-x%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=x-1\" Rearrange the terms and simplify.\r
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\n" ); document.write( "\n" ); document.write( "Now let's graph the equation:\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=x-1\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's graph the second equation:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=-1\" Start with the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-1-x\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x-1\" Rearrange the terms and simplify.\r
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\n" ); document.write( "\n" ); document.write( "Now let's graph the equation:\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=-x-1\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's graph the two equations together:\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=x-1\" (red). Graph of \"y=-x-1\" (green)\r
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\n" ); document.write( "\n" ); document.write( "From the graph, we can see that the two lines intersect at the point . So the solution to the system of equations is . This tells us that the system of equations is consistent and independent.\r
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