document.write( "Question 172826: Joe has a collection of nickles and dimes that is worth, $7.05. If the # of dimes were doubled, and the # of nicles were increased by eight, the value of the coins would be, $11.75. How many dimes does he have?\r
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document.write( "It really helps me to understand if I can See each step to solve this problem written out like in a math book. Thank you \n" );
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Algebra.Com's Answer #127675 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Let D=the number of dimes. \n" ); document.write( "Let N=the number of nickles. \n" ); document.write( ".10D+.05N=7.05 (multiply this equation by -2 & add to the other equation \n" ); document.write( ".10*2D+.05(N+8)=11.75 \n" ); document.write( ".20D+.05N+.40=11.75 \n" ); document.write( ".20D+.05N=11.75-.40 \n" ); document.write( ".20D+.05N=11.35 \n" ); document.write( "-.20D-.10N=-14.10 \n" ); document.write( "----------------------- \n" ); document.write( "-.05N=-2.75 \n" ); document.write( "N=-2.75/-.05 \n" ); document.write( "N=55 nickles. \n" ); document.write( ".10D+.05*55=7.05 \n" ); document.write( ".10D+2.75=7.05 \n" ); document.write( ".10D=7.05-2.75 \n" ); document.write( ".10D=4.30 \n" ); document.write( "D=4.30/.10 \n" ); document.write( "D=43 dimes. \n" ); document.write( "Proof: \n" ); document.write( ".20*43+.05*55=11.35 \n" ); document.write( "8.60+2.75=11.35 \n" ); document.write( "11.35=11.35 \n" ); document.write( " \n" ); document.write( " |