document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164104>Question 164104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has 60 g of a solution that is 70% acid. How much water should be added to make a solution that is 40% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127664 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has 60 g of a solution that is 70% acid. How much water should be added to make a solution that is 40% acid?<BR>\n" );
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document.write( "The original solution has 42 gm (60*0.7) of acid, 18 gm of water.<BR>\n" );
document.write( "Adding water to make 42 gm 40% means 100% will be 42/0.4 grams, = 105 grams total.<BR>\n" );
document.write( "He'll have to add 45 grams of water.  <BR>\n" );
document.write( "You'd think a chemist could figure that out himself.<BR>\n" );
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