document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=172800>Question 172800</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0028250419/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I am having a bit of trouble on this equation.\r<BR>\n" );
document.write( "\n" );
document.write( "here it is if you can please help me: -2k/7=36<BR>\n" );
document.write( "my teacher hasnt tought this to us yet </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #127650 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=127650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Dealing with fractions and equations we need to cross multiply.<BR>\n" );
document.write( "-2k/7=36/1<BR>\n" );
document.write( "The left numerator (-2k) times right denominator (1) equals the right numerator (36) times the left denominator (7). Thus we have:<BR>\n" );
document.write( "-2k*1=36*7<BR>\n" );
document.write( "-2k=252<BR>\n" );
document.write( "k=252/-2<BR>\n" );
document.write( "k=-126 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "-2*-126/7=36<BR>\n" );
document.write( "252/7=36<BR>\n" );
document.write( "36=36<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );