document.write( "Question 172780: A broker invested $13,000 in two different stocks. One earned dividends at a rate of 8% and the other at 7%. If a dividend of $1370 was earned on both stocks, how much was invested at each rate?
\n" );
document.write( "I set up the equation as follows:
\n" );
document.write( " Quantity(amount Invested)::
\n" );
document.write( "StockA = A
\n" );
document.write( "StockB = $13000 – A
\n" );
document.write( "Value(Interest rate):
\n" );
document.write( " StockA = 0.08
\n" );
document.write( " StockB = 0.07
\n" );
document.write( "Quantity * Value:
\n" );
document.write( "StockA = .08A
\n" );
document.write( "StockB = 0.07($13000 – A)= 910 -.07A [WHERE DID YOU GET THE 910 TERM?????]
\n" );
document.write( "Therefore:
\n" );
document.write( "0.08A + 910 – 0.07A = $1370
\n" );
document.write( "910 + 0.01A = $13000 = $1370
\n" );
document.write( "0.01A = $460
\n" );
document.write( "A = $46,000 ???? \r
\n" );
document.write( "\n" );
document.write( "Here is where I am lost because the broker only had $13,000 to invest. $46,000 > $13,000. What’s wrong???
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #127621 by checkley77(12844) ![]() You can put this solution on YOUR website! .08x+.07(18,000-x)=1,370 \n" ); document.write( ".08x+1,260-.07x=1,370 \n" ); document.write( ".01x=1,370-1,260 \n" ); document.write( ".01x=110 \n" ); document.write( "x=110/.01 \n" ); document.write( "x=11,000 invested @ 8%. \n" ); document.write( "18,000-11,000=7,000 invested @ 7%. \n" ); document.write( "Proof: \n" ); document.write( ".08*11,000+.07*7,000=1,370 \n" ); document.write( "880+490=1,370 \n" ); document.write( "1,370=1,370 \n" ); document.write( " |