document.write( "Question 172768: This problem is similar to another one I earlier but the answers are much different:\r
\n" ); document.write( "\n" ); document.write( "Simplify: (3x^3 - 9x -3)/(3x +3)\r
\n" ); document.write( "\n" ); document.write( "My answer: x^2 - x - 2, remainder 3\r
\n" ); document.write( "\n" ); document.write( "Problem is I have no idea where the x-2 is truly coming from. Is this correct and if so (or not) can someone please show me why?
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Algebra.Com's Answer #127603 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Write it out like a regular long division problem, but remember to put in a place holder for the missing \"x%5E2\" term in your dividend.\r
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\n" ); document.write( "\n" ); document.write( "Divisor: \"3x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "Dividend: \"3x%5E3+%2B+0x%5E2+-+9x+-+3\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x\" goes into \"3x%5E3\" \"x%5E2\" times so \"x%5E2\" becomes the first term in your quotient.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2\" times \"3\" is \"3x%5E2\" so write that (with a plus sign in front of it) under the \"0x%5E2\" in your dividend. \"x%5E2\" times \"3x\" is \"3x%5E3\" so write that under the \"3x%5E3\" in your dividend.\r
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\n" ); document.write( "\n" ); document.write( "Now subtract \"3x%5E3%2B3x%5E2\" from \"3x%5E3%2B0x%5E2\" (remember: change the sign and add) You should get \"-3x%5E2\" -- write that at the bottom of your \"x%5E2\" column.\r
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\n" ); document.write( "\n" ); document.write( "Now bring down the next term \"-9x\" from the dividend and write that next to the result of your subtraction in the previous step. You should be looking at \"-3x%5E2-9x\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x\" goes into \"-3x%5E2-9x\" \"-x\" times, so \"-x\" becomes the next term in your quotient.\r
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\n" ); document.write( "\n" ); document.write( "\"-x\" times \"3x%2B3\" is \"-3x%5E2-3x\", subtraction results in \"-6x\". Bring down the \"-3\".\r
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\n" ); document.write( "\n" ); document.write( "\"3x\" goes into \"-6x\" \"-2\" times, so \"-2\" becomes the third term in your quotient.\r
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\n" ); document.write( "\n" ); document.write( "\"-2\" times \"3x%2B3\" = \"-6x-6\", subtraction results in \"%2B3\".\r
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\n" ); document.write( "\n" ); document.write( "\"3x\" does not go into \"3\" at all, so \"3\" is a remainder.\r
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\n" ); document.write( "\n" ); document.write( "Putting the pieces of the quotient together you get: \"x%5E2-x-2\" remainder 3.\r
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\n" ); document.write( "\n" ); document.write( "Another way to express this would be \"%283x%5E3+-+9x+-3%29%2F%283x+%2B3%29=%28x%5E2-x-2%29%2B%283%2F%283x%2B3%29%29\"
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